0=10x-4.9x^2+0.7

Solution for 0=10x-4.9x^2+0.7 equation:

0=10x-4.9x^2+0.7

We move all terms to the left:

0-(10x-4.9x^2+0.7)=0

We add all the numbers together, and all the variables

-(10x-4.9x^2+0.7)=0

We get rid of parentheses

4.9x^2-10x-0.7=0

a = 4.9; b = -10; c = -0.7;
Δ = b2-4ac
Δ = -102-4·4.9·(-0.7)
Δ = 113.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-\sqrt{113.72}}{2*4.9}=\frac{10-\sqrt{113.72}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+\sqrt{113.72}}{2*4.9}=\frac{10+\sqrt{113.72}}{9.8}
$